Crack In The Pearl Pt.II (Feat. Stevie Wonder & Jeff Bhasker) (track)
by Mark Ronson
Year: 2015
From the album Uptown Special (track #11)
Listen on Spotify SPOTIFY
Crack In The Pearl Pt.II (Feat. Stevie Wonder & Jeff Bhasker) appears on the following album(s) by Mark Ronson:
- Uptown Special (track #11) (this album) (2015)
Listen to Crack In The Pearl Pt.II (Feat. Stevie Wonder & Jeff Bhasker) on YouTube
Crack In The Pearl Pt.II (Feat. Stevie Wonder & Jeff Bhasker) ratings
Average Rating = (n ÷ (n + m)) × av + (m ÷ (n + m)) × AVwhere:
av = trimmed mean average rating an item has currently received.
n = number of ratings an item has currently received.
m = minimum number of ratings required for an item to appear in a 'top-rated' chart (currently 10).
AV = the site mean average rating.
Showing latest 5 ratings for this track. | Show all 11 ratings for this track.
| Rating | Date updated | Member | Track ratings | Avg. track rating |
|---|---|---|---|---|
| 04/21/2017 00:56 |  flamingyesdept | 15,996 | 84/100 | |
| 01/25/2017 21:54 | Vasco | 8,502 | 78/100 | |
| 02/20/2016 18:57 | gelud | 17,647 | 75/100 | |
| 01/13/2016 00:28 | IAppearMissing | 2,858 | 81/100 | |
| 07/28/2015 06:15 | juanr1096 | 71,455 | 79/100 |
Rating metrics:
Outliers can be removed when calculating a mean average to dampen the effects of ratings outside the normal distribution. This figure is provided as the trimmed mean. A high standard deviation can be legitimate, but can sometimes indicate 'gaming' is occurring. Consider a simplified example* of an item receiving ratings of 100, 50, & 0. The mean average rating would be 50. However, ratings of 55, 50 & 45 could also result in the same average. The second average might be more trusted because there is more consensus around a particular rating (a lower deviation).
(*In practice, some tracks can have several thousand ratings)
This track has a Bayesian average rating of 72.7/100, a mean average of 69.5/100, and a trimmed mean (excluding outliers) of 69.5/100. The standard deviation for this track is 10.5.
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